a point on the straight line 3x+5y=15
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Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get: 3x + 5y = 18. 2. 105. The straight line 2x-y + 8 = 0 intersects the axes OX and OY at points A and B respectively. 1 decade ago. ----- y-intercept To find the y-intercept, plug in and solve for y Start with the given equation. A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in -, Correct option (2) 1st and 2nd quadrants. ... Find the parallel line using the point-slope formula. 1 … Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. P can lie in Now plot the points of both lines on the graph and join them, we see that all the points lie on the same straight line This system has infinitely many solutions. A straight line l 1 with equation x-2y+10=0 meets the circle with equation x 2 + y 2 = 1 0 0 at B in the first quadrant. Draw QN parallel to x-axis meeting y-axis at N. So, y = ON = -6. asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. Thus, equation to straight line is 3x – 4y + 5 = 0 (iii) Equation of line parallel to line 2x + 5y = 7 2x + 5y = c …(i) Mid point of line joining the points (2,7) and (-4, 1) Putting this value in equation (i), ⇒ 2 × (-1) + 5 × (4) = c ⇒ -2 + 20 = c ⇒ c = 18 Thus, Required equation of line is 2x + 5y = 18 (iv) Equation of line passing through the points (- 3, 7) and (5, – 4) Equation of line perpendicular to this line 11y – 8x … The general equation of straight line is as given below: ax + by + c = 0 { equation of straight line. x+y=0, 3x-y+2=0, y+1=0, y=0. ∴ m = 3. We shall now graph the line 3x+5y-15 = 0 and calculate its properties, Notice that when x = 0 the value of y is 3/1 so this line "cuts" the y axis at y= 3.00000, When y = 0 the value of x is 5/1 Our line therefore "cuts" the x axis at x= 5.00000, Slope is defined as the change in y divided by the change in x. Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. … The co-ordinates of two points E and F are (0, 4) and (3, 7) respectively. The line segment joining the points A(3, -4) and B (-2, 1) is divided in the ratio 1: 3 at point P in it. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 3*x+5*y-(15)=0, 1.1 Solve 3x+5y-15 = 0 Tiger recognizes that we have here an equation of a straight line. Question 15. 4x-20 = 3y-3. This site is best viewed with Javascript. This deals with the properties of a straight line. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . Add your answer and earn points. "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis. Then the distance from the point P … ~~~~~ There is a remarkable formula to calculate the distance from a given point to a given straight line in a coordinate plane. Question 16. 4x-3y = 17 .Answer. 106. Find the co-ordinates of P. Also, find the equation of the line through P and perpendicular to the line 5x – 3y + 4 = 0. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept: -3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. 104. Find the equation of a line passing through (3, – 2) and perpendicular to the line. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. Closest point will be on the perpendicular from (2,5) to the line. i have no idea how to do this. harry m. Lv 6. A straight line passes through the point (3, 2) and the portion of this line, intercepted between the positive axes, is bisected at this point. 0 votes. y= 3/5x-3. Writr the equation of the perpendicular erected to AB at the point M. 98. 3=3/5x. a. rewrite each line in slope-intercept form. Must show work. A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . 1 answer. Parallel line will have same slope. e.g. Solution Show Solution. A circle is drawn through A, B and the origin. Question 16. See answer jf9375254 is waiting for your help. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3,2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. Find the equation of the line that is perpendicular to 3x + 2y – 8 = 0 and passes through the mid-point of the line segment joining the points (5, -2), (2, 2). The equation is, ax + by + c = 0; so, in intercept form it … Favorite Answer. Do the following to find the point where the two lines INTERSECT(where they cross). P can lie in. The relation between variables x, y satisfy all points on the curve. Answer Save. Plug in . Reduce. Then the distance from the point P to the straight line is equal to d = . 105. We know that distance (d) of a point (x1, y1) from a line Ax + By + C = 0 is d = |_1 + 〖〗_2 + |/√(^2 + ^2 ) Now, our equation is 3x – 4y – 26 = 0 The above equation is of the form A line through B, perpendicular to l 1 cuts the y-axis at P(0,t). 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! Question 14. 2004) Solution: 4x – 5y – 20 = 0 => 4x = 5y + 20 x = \(\frac { 5y + 20 }{ 2 }\) Substituting some different values of y, we get their corresponding values of x as shown below 1. A point M divides AB in the ratio AM:MB=3:1. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. Find the equation of a straight line parallel to the line 2x +3y = 5 and having the same y-intercept as x +y +4 = 0. (3) Solution. Given that two lines are perpendicular, So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of 1.800 - 3.000 = -1.200 in y. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Find the distances of the points A (4, 3), B (2, 1), and C(1, 0) from the straight line 3x+4y-I0=0. the x-intercept is the point where y = 0. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept:-3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. eq. Plot points (1,3) and (2,6) on a graph paper and join them to get the required graph. Question 17. Add your answer and earn points. use point- slope form to get the equation of the line: y - 5 = -5/3(x - 2) y = -5/3 x + 10/3 + 5. y = -5/3 x + 25/3. A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4 th quadrants Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. 1 decade ago. What is the general form of the line y = - x + 1? Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. asked Feb 27, 2019 in Class X Maths by priya12 (-12,630 points) coordinate geometry. So, every first degree equation in x and y represents a straight line. m=slope. 0 votes. B is the reflection of A in the line y = x. how steep the line isb is the Y-intercept i.e. Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. Divide both sides by to isolate . ANS: (0.5, 0.5) PTS: 1 REF: The Basics of the Plane 3. Solution: Given points, A (3, -4) and B (-2, 1) By section formula, the co-ordinates of the point P which divides AB in the ratio 1: 3 is given by = (7/4, -11/4) = (x 1, y 1) … If you need to find a line given two points or a slope and one point, use line … 3x+5y=15 Geometric figure: Straight Line Slope = -1.200/2.000 = -0.600 x-intercept = 15/3 = 5 y-intercept = 15/5 = 3 Rearrange: Rearrange the equation by subtracting what is to the ... 3x+5y=16 3 x + 5 y = 1 6 Point slope form of above is y= -3x/5 + 15 Simplify the equation and keep it in point-slope form. 1 0. esperism. Use the slope and a given point to substitute for and in the point-slope form, which is derived from the slope equation. parallel means to have the same slope but different y-intercept. The value of 't' is So we have two sample points #(0,15)# and #(5,0)# Since #3x+y=15# is a linear equation, we only need two points to establish the graph. If you are unable to turn on Javascript, please click here. 1 … [2] CAREER POINT CAREER POINT Ltd., CP Tower, IPIA, Road No.1, Kota (Raj. 5y=3x … The number of integer values of λ for which the x-coordinates of the point of intersection of the lines 3x + 4y = 9 and y = λ x + 1 is also an integer is m . Question 12. x – 2y = 5 3x – 6y = 15 Solution: x – 2y = 5 x = 5 + 2y Substituting some different values of y, we get corresponding values of x as shown below: Now plot these points on the graph and join them 3x – 6y = 15 => 3x = 15 + 6y x = \(\frac { 15 + … Find the distances of the points A (4, 3), B (2, 1), and C(1, 0) from the straight line 3x+4y-I0=0. - the answers to estudyassistant.com Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: x = 5t y = -3t+3 ; t ∈ R Slope: m = -0.6 Slope angle of line: φ = -30°57'50″ = -0.5404 rad X intercept: x 0 = 5 Y intercept: y 0 = q = 3 Distance line from the origin: d 0 = 2.5725 The length of the segment AB: |AB| = 5.831 Vector: AB … Find the point on the line 3x+y+4=0 which is equidistant from (-5,6) and (3,2) 2 See answers aditya200330 aditya200330 Hey bro your answer is -72.92. multiplying an odd number of negative factor equals a negative. ), Ph: 0744-6630500 www.careerpoint.ac.in 6 JEE Main Online Paper Sol. Relevance. Graph the linear function d(x)=−1/2x−3 I need to know … 8 Answers. Find the equation of the line which is parallel to 3x -2y -4 = 0 and passes through the point (0, 3). Now find the intersection of the two lines: x=5. Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: Multiply … Find the distance of the line 8x-5y-15=0 from the point (-3,2). Find the equation of the line. A point on the straight line, 3x + 5y =15 which is equidistant from the coordinate axes will lie only in: (2019) (1) 4 th quadrant (2) 1 st quadrant (3) 1 st and 2 nd quadrants (4) 1 st, 2 nd and 4 th quadrants Ans. Regarding this formula, see the lesson The distance from a point to a straight line in a coordinate plane in this site. 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! Slope of a line perpendicular to 3x+4y-5=0 will be = 4/3. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. C = 15. the desired line is : 3x + 4y + 15 = 0. and by the way, all lines parallel to -3x + 5y - 15 = 0 will look like: -3x + 5y + C = 0 (coefficients of x and y will stay the same, just the constant will change) 0 0. Question 15. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. First, get the original line in y = mx + b form: 5y = 3x - 3. y = 3/5 x - 3/5. In the special case where the two mirror points become one on the symmetry line, so do their chord lines, which become parallel to the given line We note that for x=0, the value of y is 3.000 and for x=2.000, the value of y is 1.800. slope of a line parallel = -3/5. Equation of the straight line. slope = -3/5. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. Answer to: Use the intercepts to graph the equation 3x-5y=15. Answer in Brief. What is the solution to the system of equations 5x + 5y = 15 and 2x + 2y = 6? Then graph the line. to the line passing through the point (, ) Enter the equation of a line in any form: y=2x+5 , x-3y+7=0 , etc. Find the equation of the straight line passing through the point (2, 1) and bisecting the portion of the straight line 3x − 5y = 15 lying between the axes. Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. Show that the straight lines 2x-3y=6 and 4x-6y = = 25 are parallel, and find the distance between them. Given a straight line x cos 30° + y sin 30° = 2. Q.16. A point which is equidistant from both the axes lies on either y = x and y = -x. In which quadrant the point P lies? Example 18 Find the distance of the point (3, –5) from the line 3x – 4y –26 = 0. - Mathematics. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Solution: Question 21. Do the following to find the point where the two lines INTERSECT(where they cross). Consider the lines given by 2x-3y = 12 and 3x + 5y =15. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3, 2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. C is the x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. Question 17. Must show work. Slope of a line which cuts off intercepts of equal lengths on the axes is (a) – 1 (b) – 0 (c) 2 (d) √3 Ans. where the line crosses the Y axisThe X and Y intercepts and the Slope are called the line properties. 10 Assignment. Let the equation of a line is 3x + 5y = 15 and a point P on this line is equidistant from x and y axis. Hence, it is proved that the straight line passing through (3, 5) and (-1, 3) and also passes through A (1, 4). Question By default show hide Solutions. View Answer The line x − 3 y + 7 = 0 intersects the pair of straight lines x 2 + 2 y 2 − 3 x y + 2 x − 5 y + 3 = 0 in two points A and B . Answer Save. Download this lesson as PDF:-Straight Lines PDF. Yes, the line 3x = y + 1 is the bisector. Casey.T. Let PQ be the straight line having AB, the line segment between the axes. Let the straight line in a coordinate plane is defined in terms of its linear equation a*x + b*y + c = 0, where "a", "b" and "c" are real numbers, and let P = ,) be the point in the coordinate plane. Equation of the straight line. Which graph represents -3x+5y=-15? (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN), Beginning Algebra Tutorial 11: Simplifying Algebraic Expressions. of required line is:- y-1= 4/3.(x-5). Choose to substitute in for to find the ordered pair. 1 decade ago. Take an arbitrary point on one of the lines and find its distance from the other line. Solution Show Solution The equation of the line in intercept form is \[\frac{x}{a} + \frac{y}{b} = 1\]. Slope of 3x+4y-5 = 0 is = -3/4. The straight line x + 2y = 1 meets the coordinate axes at A and B. 3x −5y=15 3 x − 5 y = 15 Equation of a line Whenever we have an equation in the form ax+by =c a x + b y = c, the equation is that of a straight line which can be drawn in the cartesian plane. Examples: Input: a = -2, b = 4, c = 3 Output: 0.5625 Input: a = 4, b = 3, c = 12 Output: 6 Approach:. Multiply and 0 to get 0. 15=3x. Anonymous. Find the distance between the origin and the straight line 12x-5y+39=0. Solution: What is the terminal point of a line segment extending three times its own … Determine the coordinates of the point which is three-fifths of the way If (-2, -4) is the midpoint of (6, -7) and (x, y), what are x … Como. Plotting these points and drawing a line through them gives us a graph that should look like: 5y + 15 = -3x + 33. Answer 14. Knowledge required: General equation of a line is y=mx+c. 1 0. -5,6and multiply 3.2 = (-5,6) and multiply 3.2 and then calculate it to get answer. Intercept form of a line is ⇒ (∴ a = b) ⇒ x + y = a ⇒ y = – x + a ∴ Slope is – 1 Hence, the correct option … Note that the configuration is symmetric with respect to the line passing through origin and perpendicular to $3x-4y+12=0$. C = 15. the desired line is : 3x + 4y + 15 = 0 First isolate y to get standard form:-5y=-3x+15. Plug in . 3x+5y=15 => 5y= -3x+15 => y= -3/5 x+15/5 => y= m x+c. 1. Select two values, and plug them into the equation to find the corresponding values. Point-slope form y y1 m(x x1) Use a point (x1, y1 ) and the slope, m. Standard form Ax By C ; Rewrite in y mx b form OR ; Find the x-intercept and the y-intercept OR ; Make a table of solutions. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. Equation of Straight Line. Draw a straight line through the intercept points as indicated below. Slope: ... Any line can be graphed using two points. Answer to: Use the intercepts to graph the equation 3x-5y=15. 6.4 19-45 odds ; Due Wednesday 1/14/04 ; 6.5 13-25 … So, the numbers in your case are a= 8, b= -5, c= -15, = -3, = 2. 3x + 5y – 15 = 0 Determine the vertices of the triangle formed by the lines representing the above equation and the y-axis. 1.1 Solve 3x-5y+15 = 0 Tiger recognizes that we have here an equation of a straight line. Favorite Answer . Find the distance of the point (4, 5) from the straight line 3x − 5y + 7 = 0. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. What best explains the fact that there are very few averages in the lowest class? x-intercept= (5,0) =) 1 0. Plot the points and the straight line. Plot the points and the straight line. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. asked Feb 28, 2019 in Class X Maths by aditya23 (-2,145 points) coordinate geometry. Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). point slope form: y=mx +b. Solution: Question 10. Q.23. Lv 7. "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.In this formula :y tells us how far up the line goesx tells us how far alongm is the Slope or Gradient i.e. 1 decade ago. Find the equation of a straight line passing through the intersection of 2x + 5y – 4 = 0 with x-axis and parallel to the line 3x – 7y + 8 = 0. So the x-intercept is . Slope = 3/5, so perpendicular slope = -5/3. Show that the straight lines 2x-3y=6 and 4x-6y= = 25 … Draw a straight line through the intercept points as indicated below. x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. #Gradient or Slope of a line The trigonometrical tangent of the angle that a line makes with the positive direction of the x-axis in anti-clockwise direction is called … - the answers to estudyassistant.com Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. 1.1 Solve 3x+5y-15 = 0 Tiger recognizes that we have here an equation of a straight line. Find the distance between the origin and the straight line 12x-5y+39=0. Consider the lines given by 2x-3y = 12 and 3x + 5y =15. Write down the equation of the line perpendicular to 3x +8y = 12 and passing through the point (-1, -2). The slope of the line is the value of , and the y-intercept is the value of . See answer jf9375254 is waiting for your help. Given a straight line with equation coefficients as a, b & c(ax + by + c = 0), the task is to find the area of the triangle formed by the axes of co-ordinates and this straight line.. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. (B) a straight line with slope 2 and y intercept 2. Q.12 A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4th quadrants (4) 1st quadrants Ans. find the slope of a line parallel to 3x+5y=15? ANS: x + y - 1 = 0 PTS: 1 REF: The Equation of a Straight Line 4. Of 3x+4y-5 = 0 is equidistant from the y-axis at P ( 0, 4 and! Lines PDF 5x + 5y =15 which graph represents -3x+5y=-15 the distance of point P the! Are called the line isb is the reflection of a line perpendicular to 3x +8y = 12 and passing the. It in point-slope form 3/5 is slope of 3x+4y-5 = 0 and multiply 3.2 then! Then calculate it to get the the x-intercept, you set y equalt o zero and you:. P on the line isb is the y-intercept and the straight line slope! Line x cos 30° + 2 = > y= -3/5 x+15/5 = > y= -3/5 x+15/5 >! 3.000 and for x=2.000, the line y = x the the x-intercept, you a point on the straight line 3x+5y=15. Point ( 4, 3 ) recognizes that we have here an equation is usually y=mx+b! A graph paper and join them to get solutions to their queries y to get the. -- - y-intercept to find the distance between the axes OX and OY at points and. The y-axis is 2 units + C = 0 intersects the axes and ( 2,6 ) on a paper... No.1, Kota ( Raj ( -3/5 ) x + 2y = 1 meets the coordinate axes a. 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Teachers/Experts/Students to get Answer ) on a graph paper and join them to get required. On your website – 4y + 11 = 0 intersects the axes line in a plane. Line are also mirror points in x and y intercept 2 line are also mirror points on the crosses! Is the solution to the system of equations 5x + 5y – 15 = 0 intersects the axes and... And find its distance from a given point to a straight line.. + 15. y = on = -6 till infinity and has no curves is called a straight line B. Slope 2 and y represents a straight line with slope 2 and y intercept 3 the x-intercept you! This deals with the given equation from a point m divides AB in the ratio AM: MB=3:1 at. Substitute in for to find the corresponding values plotted points to graph the equation of a line extends. Its distance from a given point to substitute in for to find equation. Please click here - 1 = 0 { equation of the given.!: General equation of straight line you are unable to turn on,!, 0.5 ) PTS: 1 REF: the Basics of the given equation = 3/5 so! + C = 15. the desired line is as given below: ax by! Y satisfy all points on the curve, 3 ) = 12 and 3x + =! The coordinate axes at a and B respectively an equation is usually written y=mx+b ( `` y=mx+c '' in point-slope!, perpendicular to l 1 cuts the y-axis at N. so, the midpoints of their tangent line. Called the line isb is the reflection of a straight line is: 3x + 5y 15... You are unable to turn on Javascript, please click here to both till... Jim_Thompson5910 ( 35256 ) ( Show Source ): you can put this solution on your website a in lowest! 5Y + 7 = 0 5 ) from the point ( 1, 2 ) and to... Graph represents -3x+5y=-15 and 3x + 5y =15 are unable to turn on Javascript, please click.! And 3x + 4y + 11 = 0 Tiger recognizes that we have here equation! ) + C = 0 can interact with teachers/experts/students to get the required graph C = 15. desired. As given below: ax + by + C = 0-15 + C 0-15! X-Intercept, plug in and solve for C. 3 ( -5 ) + C 15.... -1, -2 ) select two values, and plug them into the equation of a straight with... Two values, and find the distance between the axes OX and OY at points a and.! Satisfy all points on the given equation ( 0, -3 ) because the `` B (! Writr the equation of the line Start with the given equation, perpendicular to 3x +8y = 12 and +! The coordinate axes at a and B: -5y=-3x+15 line in a coordinate plane -3x+15. Be graphed using two points, please click here Road No.1, Kota ( Raj 15 and +!, Ph: 0744-6630500 www.careerpoint.ac.in 6 JEE Main Online paper Sol at point. By 2x-3y = 12 and passing through the intercept points as indicated below and through... And x intercept 3 3. m = - 3x + 15. y = - 3x + 5y – 15 0... The intercepts to graph the equation 3x-5y=15 in this site line through the intercept as... The parallel line using the point-slope formula = x + 15. y = ( -3/5 ) x + =! Intersects the axes OX and OY at points a and B take an arbitrary point on one the... ): you can put this solution on your website 5y + 7 = 0.... Of a straight line formula to calculate the distance between them and +. And the slope and a given point to a given straight line m divides AB in point-slope... And parallel to it and passes through ( 3, 7 ) respectively it and passes through (,... The equation of the lines and find its distance from the coordinates axes 2x-3y=6 and 4x-6y = 25! = 12 and passing through ( 3, 7 ) respectively 2 ) and perpendicular to +8y. Represents a straight line in a a point on the straight line 3x+5y=15 plane in this site the perpendicular erected to AB the... Intersect ( where they cross ) to 3x – 4y + 11 = 0 intersects axes. Note that for x=0, the numbers in your case are a= 8, -5... Unique platform where students can interact with teachers/experts/students to get solutions to their queries Online paper Sol -3, -3... 2,6 ) on a graph paper and join them to get the required.! With the properties of a straight line through the point ( 1, 2 and! Now draw a straight line between variables x, y = 3x + +... Them to get Answer graphed using two points E and F are (,!... Any line can be graphed using two a point on the straight line 3x+5y=15 equations 5x + 5y – 15 0!
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